If in two triangles ABC and PQR,frac{AB}{QR} | vedclass

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(B) Given,in two triangles $ABC$ and $PQR$,$\frac{AB}{QR} = \frac{BC}{PR} = \frac{CA}{PQ}$.This ratio shows that the sides of $	riangle ABC$ are prop

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$	riangle PQR \sim 	riangle CAB$

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(B) Given,in two triangles $ABC$ and $PQR$,$\frac{AB}{QR} = \frac{BC}{PR} = \frac{CA}{PQ}$.This ratio shows that the sides of $	riangle ABC$ are proportional to the corresponding sides of $	riangle PQR$.Specifically,the side $AB$ corresponds to $QR$,$BC$ corresponds to $PR$,and $CA$ corresponds to $PQ$.By the $SSS$ (Side-Side-Side) similarity criterion,if the sides of two triangles are in the same ratio,then the triangles are similar,and their corresponding angles are equal.Matching the vertices based on the proportionality:$A$ corresponds to $Q$,$B$ corresponds to $R$,and $C$ corresponds to $P$.Therefore,$	riangle ABC \sim 	riangle QRP$,or equivalently,$	riangle CAB \sim 	riangle PQR$.

If in two triangles $ABC$ and $PQR$,$\frac{AB}{QR} = \frac{BC}{PR} = \frac{CA}{PQ}$,then

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