If the slope of the line ax + (3 - a)y + 7 = | vedclass

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(A) The equation of the line is given by $ax + (3 - a)y + 7 = 0$. We know that the slope of a line $Ax + By + C = 0$ is given by $m = -\frac{A}{B}$. H

Vedclass · Accepted Answer

$3$

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(A) The equation of the line is given by $ax + (3 - a)y + 7 = 0$. We know that the slope of a line $Ax + By + C = 0$ is given by $m = -\frac{A}{B}$. Here,$A = a$ and $B = (3 - a)$. Given that the slope $m = 7$,we have: $-\frac{a}{3 - a} = 7$ $\frac{a}{a - 3} = 7$ $a = 7(a - 3)$ $a = 7a - 21$ $6a = 21$ $a = \frac{21}{6} = 3.5$. The integral part of $a$,denoted as $[a]$,is the greatest integer less than or equal to $a$. $[3.5] = 3$. Therefore,the correct option is $A$.

If the slope of the line $ax + (3 - a)y + 7 = 0$ is $7$,then the value of the integral part of '$a$' is

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