In Delta ABC and Delta XYZ,angle A cong angle | vedclass

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(D) Given that in $\Delta ABC$ and $\Delta XYZ$,$\angle A = \angle Y$ and $\angle B = \angle Z$.By the $AA$ (Angle-Angle) similarity criterion,$\Delta

Vedclass · Accepted Answer

$9.8$

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(D) Given that in $\Delta ABC$ and $\Delta XYZ$,$\angle A = \angle Y$ and $\angle B = \angle Z$.By the $AA$ (Angle-Angle) similarity criterion,$\Delta ABC \sim \Delta YZX$.Since the triangles are similar,the ratios of their corresponding sides are equal:$\frac{AB}{YZ} = \frac{BC}{ZX} = \frac{AC}{YX}$.We are given $\frac{AC}{YX} = \frac{5}{7}$ and $AB = 7$.Substituting these values into the ratio $\frac{AB}{YZ} = \frac{AC}{YX}$,we get:$\frac{7}{YZ} = \frac{5}{7}$.Cross-multiplying gives $5 	imes YZ = 7 	imes 7$.$5 	imes YZ = 49$.$YZ = \frac{49}{5} = 9.8$.

In $\Delta ABC$ and $\Delta XYZ$,$\angle A \cong \angle Y$ and $\angle B \cong \angle Z$. If $\frac{AC}{YX} = \frac{5}{7}$ and $AB = 7$,find $YZ$.

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