In Delta PQR,angle P = 42^{circ} and angle Q | vedclass

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(C) The sum of all interior angles of a triangle is always $180^{\circ}$.In $\Delta PQR$,we have $\angle P + \angle Q + \angle R = 180^{\circ}$.Given

Vedclass · Accepted Answer

$63$

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(C) The sum of all interior angles of a triangle is always $180^{\circ}$.In $\Delta PQR$,we have $\angle P + \angle Q + \angle R = 180^{\circ}$.Given $\angle P = 42^{\circ}$ and $\angle Q = 75^{\circ}$.Substituting these values: $42^{\circ} + 75^{\circ} + \angle R = 180^{\circ}$.$117^{\circ} + \angle R = 180^{\circ}$.$\angle R = 180^{\circ} - 117^{\circ} = 63^{\circ}$.

In $\Delta PQR$,$\angle P = 42^{\circ}$ and $\angle Q = 75^{\circ}$,then find $\angle R$. (in $^{\circ}$)

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