In $\triangle ABC$,if $A = 60^{\circ}$ and $B = 105^{\circ}$,then find the value of $\frac{2R^2(b-c) \sin A \sin B \sin C}{(b+c)(s-a \cos C - c \cos A)(s-a \cos B - b \cos A)}$.

  • A
    $\frac{1}{\sqrt{2}}$
  • B
    $\sqrt{3}$
  • C
    $1$
  • D
    $\frac{1}{\sqrt{3}}$

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