In an NPN transistor,the collector current is | vedclass

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(C) Given that the collector current $I_C = 20 \, mA$. Since $90\%$ of the emitted electrons reach the collector,the collector current is $90\%$ of th

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Base current will be $2 \, mA$

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(C) Given that the collector current $I_C = 20 \, mA$. Since $90\%$ of the emitted electrons reach the collector,the collector current is $90\%$ of the emitter current $(I_E)$. So,$I_C = 0.90 	imes I_E$. $I_E = \frac{I_C}{0.90} = \frac{20}{0.90} \approx 22.22 \, mA$. The base current is given by $I_B = I_E - I_C$. $I_B = 22.22 \, mA - 20 \, mA = 2.22 \, mA$. Comparing this with the given options,the most appropriate choice is that the base current is $2 \, mA$ (approximately) or the emitter current is $22.22 \, mA$.

In an $NPN$ transistor,the collector current is $20 \, mA$. If $90\%$ of the electrons emitted reach the collector,then:

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