In a common emitter transistor amplifier,the output voltage and input voltage have a phase difference of

  • A
    $0^c$
  • B
    $\frac{\pi^c}{2}$
  • C
    $\frac{3 \pi^c}{4}$
  • D
    $\pi^c$

Explore More

Similar Questions

In a $PNP$ transistor,the base is the $N$-region. Its width relative to the $P$-region is

$A$ transistor is used as a common emitter amplifier with a load resistance $2 \ k\Omega$. The input resistance is $150 \ \Omega$. The base current is changed by $20 \ \mu A$,which results in a change in collector current by $1.5 \ mA$. The voltage gain of the amplifier is

The current gain for a transistor working as a common base amplifier is $0.96$. If the emitter current is $7.2 \,mA$, then the base current is (in $\,mA$)

For a $CE$ amplifier,current gain is $69$. If the emitter current is $7\, mA$,then the base current and collector current will be:

Difficult
View Solution

In an $n-p-n$ transistor,in $CE$ configuration:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo