In a moderately asymmetrical distribution,the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a moderately asymmetrical distribution,the empirical relationship between mean,median,and mode is given by:$	ext{Mode} = 3 	imes 	ext{Media

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(B) For a moderately asymmetrical distribution,the empirical relationship between mean,median,and mode is given by:$	ext{Mode} = 3 	imes 	ext{Median} - 2 	imes 	ext{Mean}$Given:$	ext{Mode} = 7$$	ext{Mean} = 4$Substituting the values into the formula:$7 = 3 	imes 	ext{Median} - 2 	imes 4$$7 = 3 	imes 	ext{Median} - 8$$7 + 8 = 3 	imes 	ext{Median}$$15 = 3 	imes 	ext{Median}$$	ext{Median} = \frac{15}{3} = 5$Therefore,the median is $5$.

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$
$f_i$	$2$	$18$	$30$	$45$	$35$	$20$	$6$	$3$

In a moderately asymmetrical distribution,the mode and mean are $7$ and $4$ respectively. The median is:

Similar Questions

Find the mode of the given frequency distribution.

Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$

$f_i$ $2$ $18$ $30$ $45$ $35$ $20$ $6$ $3$

For a continuous series,the mode is computed by the formula:

The sum of the absolute deviations is minimum when taken with respect to:

If the mode of a distribution is $18$ and the mean is $24$,then what is the median?

Find the mode of the following distribution:

Marks $4$ $5$ $6$ $7$ $8$

No. of students $6$ $7$ $10$ $8$ $3$

Vedclass Test Series

Exam Paper Generator

Online Exam Module