In calculating the mean of grouped data,grouped in classes of equal width,we may use the formula $\bar{x} = a + \frac{\sum f_i d_i}{\sum f_i}$,where $a$ is the assumed mean. $a$ must be one of the mid-points of the classes. Is the last statement correct? Justify your answer.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) No,the statement is incorrect. While it is common practice to choose the assumed mean $a$ as one of the class marks (mid-points) to simplify calculations,it is not a mathematical requirement. The assumed mean $a$ can be any arbitrary value chosen from the data set or even outside it,provided it helps in simplifying the calculation of deviations $d_i = x_i - a$.

Explore More

Similar Questions

The following table gives the number of pages written by Sarika for completing her own book over $30$ days:
Number of pages written per day $16-18$ $19-21$ $22-24$ $25-27$ $28-30$
Number of days $1$ $3$ $4$ $9$ $13$

Find the mean number of pages written per day.

For a given frequency distribution,$A=49.5, \Sigma f_{i}=40, \Sigma f_{i} u_{i}=-5$ and $c=20$. Then,mean $\bar{x}=$ ............

Rachana had an average score of $45$ from $6$ tests. Her teacher dropped her lowest score,which is $30$,and calculated the average of the remaining scores to decide her grade. Which of the following gives her new average score?

In the formula $\bar{x} = A + \frac{\Sigma f_{i} u_{i}}{\Sigma f_{i}} \times c$,$c$ represents .......

Find the mean of the following frequency distribution:
Class $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$
Frequency $2$ $10$ $40$ $25$ $13$ $10$
(in $.7$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo