In the given circuit,the Zener breakdown volt | vedclass

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(D) Given: Zener breakdown voltage $V_Z = 8 \ V$,Power $P = 1.6 \ W$,Input voltage $V_{in} = 10 \ V$.$1$. Calculate the current through the Zener diod

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$10$

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(D) Given: Zener breakdown voltage $V_Z = 8 \ V$,Power $P = 1.6 \ W$,Input voltage $V_{in} = 10 \ V$.$1$. Calculate the current through the Zener diode $(I_Z)$:$P = V_Z 	imes I_Z$$1.6 = 8 	imes I_Z$$I_Z = \frac{1.6}{8} = 0.2 \ A$$2$. Calculate the voltage drop across the resistor $R$ $(V_R)$:Since the Zener diode is in parallel with the output,the voltage across it is constant at $8 \ V$.$V_R = V_{in} - V_Z = 10 \ V - 8 \ V = 2 \ V$$3$. Calculate the resistance $R$:Using Ohm's law,$V_R = I_Z 	imes R$$2 = 0.2 	imes R$$R = \frac{2}{0.2} = 10 \ \Omega$Therefore,the value of $R$ is $10 \ \Omega$.

In the given circuit,the Zener breakdown voltage is $8 \ V$. If the power of the Zener diode is $1.6 \ W$,the value of $R$ is (in $\Omega$)

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