Let $\vec{a} = \hat{i} + 2\hat{j}$ and $\vec{b} = 2\hat{i} + \hat{j}$. Is $|\vec{a}| = |\vec{b}|$? Are the vectors $\vec{a}$ and $\vec{b}$ equal?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Given vectors are $\vec{a} = \hat{i} + 2\hat{j}$ and $\vec{b} = 2\hat{i} + \hat{j}$.
The magnitude of vector $\vec{a}$ is $|\vec{a}| = \sqrt{1^{2} + 2^{2}} = \sqrt{1 + 4} = \sqrt{5}$.
The magnitude of vector $\vec{b}$ is $|\vec{b}| = \sqrt{2^{2} + 1^{2}} = \sqrt{4 + 1} = \sqrt{5}$.
Since $|\vec{a}| = \sqrt{5}$ and $|\vec{b}| = \sqrt{5}$,we have $|\vec{a}| = |\vec{b}|$.
Two vectors are equal if and only if their corresponding components are equal. Here,the components of $\vec{a}$ are $(1, 2)$ and the components of $\vec{b}$ are $(2, 1)$.
Since $(1, 2) \neq (2, 1)$,the vectors $\vec{a}$ and $\vec{b}$ are not equal.

Explore More

Similar Questions

The angle made by the position vector of the point $(5, -4, -3)$ with the positive direction of the $X$-axis is:

Which of the following is not a unit vector for all values of $\theta$?

If the points with position vectors $(\alpha \hat{i}+10 \hat{j}+13 \hat{k})$,$(6 \hat{i}+11 \hat{j}+11 \hat{k})$,and $(\frac{9}{2} \hat{i}+\beta \hat{j}-8 \hat{k})$ are collinear,then $(19 \alpha-6 \beta)^2=$

Compute the magnitude of the following vectors:
$\vec{a}=\hat{i}+\hat{j}+\hat{k} ; \quad \vec{b}=2 \hat{i}-7 \hat{j}-3 \hat{k} ; \quad \vec{c}=\frac{1}{\sqrt{3}} \hat{i}+\frac{1}{\sqrt{3}} \hat{j}-\frac{1}{\sqrt{3}} \hat{k}$

In the figure,a vector $x$ satisfies the equation $x - w = v$. Then $x =$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo