ધારો કે $A = \int\limits_0^1 \frac{e^t}{1 + t} \, dt$. તો $\int\limits_{a - 1}^a \frac{e^{-t}}{t - a - 1} \, dt$ નું મૂલ્ય શોધો:

  • A
    $Ae^{-a}$
  • B
    $-Ae^{-a}$
  • C
    $-ae^{-a}$
  • D
    $Ae^a$

Explore More

Similar Questions

$\int_{-4}^{4} (2^x + 2^{-x})(3^x + 3^{-x}) \, dx$ ની કિંમત શોધો.

ધારો કે $[\bullet]$ એ મહત્તમ પૂર્ણાંક વિધેય છે. જો $\alpha = \int_{0}^{64} (x^{1/3} - [x^{1/3}]) dx$ હોય, તો $\frac{1}{\pi} \int_{0}^{\alpha\pi} \left( \frac{\sin^2 \theta}{\sin^6 \theta + \cos^6 \theta} \right) d\theta$ ની કિંમત . . . . . . થાય.

$\int_{ - 1}^1 {\frac{{\sin x - {x^2}}}{{3 - |x|}}\,dx} $ ની કિંમત શોધો.

$\int_1^3 \left[ \tan^{-1} \left( \frac{x}{x^2-1} \right) + \tan^{-1} \left( \frac{x^2-1}{x} \right) \right] dx =$

$\int_0^1 x(1-x)^n dx =$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo