Resolve into factors: 4 x^{2}+12 x y+9 y^{2}- | vedclass

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Question

(B) Given expression: $4 x^{2}+12 x y+9 y^{2}-8 x-12 y$First,observe that the first three terms form a perfect square:$4 x^{2}+12 x y+9 y^{2} = (2 x)^

Vedclass · Accepted Answer

$(2 x+3 y)(2 x+3 y-4)$

Vedclass · Answer

(B) Given expression: $4 x^{2}+12 x y+9 y^{2}-8 x-12 y$First,observe that the first three terms form a perfect square:$4 x^{2}+12 x y+9 y^{2} = (2 x)^{2} + 2(2 x)(3 y) + (3 y)^{2} = (2 x+3 y)^{2}$Next,factor out $-4$ from the remaining two terms:$-8 x-12 y = -4(2 x+3 y)$Combining these,we get:$(2 x+3 y)^{2} - 4(2 x+3 y)$Now,factor out the common term $(2 x+3 y)$:$(2 x+3 y)(2 x+3 y-4)$Thus,the correct option is $B$.

Resolve into factors: $4 x^{2}+12 x y+9 y^{2}-8 x-12 y$

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