Roots of $ax^2 + b = 0$ are real and distinct if

  • A
    $ab > 0$
  • B
    $ab < 0$
  • C
    $a, b > 0$
  • D
    $a, b < 0$

Explore More

Similar Questions

The sum of the roots of the equation,${x^2} + |2x - 3| - 4 = 0$,is

Difficult
View Solution

Solve the given two equations and select the correct answer from the given options.
$I.$ $(441)^{\frac{1}{2}} x^{2} - 111 = (15)^{2}$
$II.$ $\sqrt{121} y^{2} + (6)^{3} = 260$

Difficult
View Solution

If the roots of the equation $\frac{x^2 - bx}{ax - c} = \frac{m - 1}{m + 1}$ are equal but opposite in sign,then the value of $m$ is:

If the difference of the roots of $x^2 - px + 8 = 0$ is $2$,then the value of $p$ is

If $a, b, c, d$ and $p$ are distinct real numbers such that $(a^2 + b^2 + c^2)p^2 - 2p(ab + bc + cd) + (b^2 + c^2 + d^2) \le 0$,then

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo