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(B) Let the breadth of the rectangle be $b 	ext{ cm}$.Then,the length of the rectangle is $l = b + 3 	ext{ cm}$.The area of the rectangle is $A = l

Vedclass · Accepted Answer

$5 	imes 2 	ext{ cm}$

Vedclass · Answer

(B) Let the breadth of the rectangle be $b 	ext{ cm}$.Then,the length of the rectangle is $l = b + 3 	ext{ cm}$.The area of the rectangle is $A = l 	imes b = (b + 3)b = b^2 + 3b$.The area of the circle with radius $r = \frac{\sqrt{35}}{\sqrt{11}} 	ext{ cm}$ is $A = \pi r^2 = \frac{22}{7} 	imes \left(\frac{\sqrt{35}}{\sqrt{11}}ight)^2$.$A = \frac{22}{7} 	imes \frac{35}{11} = 2 	imes 5 = 10 	ext{ cm}^2$.Equating the areas: $b^2 + 3b = 10$.$b^2 + 3b - 10 = 0$.$(b + 5)(b - 2) = 0$.Since breadth cannot be negative,$b = 2 	ext{ cm}$.Therefore,the length is $l = 2 + 3 = 5 	ext{ cm}$.The dimensions of the rectangle are $5 	ext{ cm} 	imes 2 	ext{ cm}$.

The area of a rectangle is the same as that of a circle of radius $\frac{\sqrt{35}}{\sqrt{11}} \text{ cm}$. If the length of the rectangle exceeds its breadth by $3 \text{ cm}$,find the dimensions of the rectangle.

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