The ground state electronic configuration of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. The $CO$ molecule has a total of $14$ electrons ($6$ from $C$ and $8$ from $O$).$2$. The core electrons ($1s^2$ of $C$ and $1s^2$ of $O$) are

Vedclass · Accepted Answer

$KK \sigma 2s^2 \sigma^* 2s^2 \pi 2p_x^2 \pi 2p_y^2 \sigma 2p_z^2$

Vedclass · Answer

(A) $1$. The $CO$ molecule has a total of $14$ electrons ($6$ from $C$ and $8$ from $O$).$2$. The core electrons ($1s^2$ of $C$ and $1s^2$ of $O$) are represented as $KK$.$3$. The remaining $10$ valence electrons are filled in molecular orbitals according to the energy order for $N_2$ and $CO$ ($14$ electrons or fewer): $\sigma 2s $4$. Filling the $10$ valence electrons: $\sigma 2s^2, \sigma^* 2s^2, \pi 2p_x^2, \pi 2p_y^2, \sigma 2p_z^2$.$5$. Thus, the configuration is $KK \sigma 2s^2 \sigma^* 2s^2 \pi 2p_x^2 \pi 2p_y^2 \sigma 2p_z^2$.

The ground state electronic configuration of the $CO$ molecule (considering only valence electrons) is represented as:

Similar Questions

When $O_{2}$ is converted into $O_{2}^{+}$,what happens to its paramagnetic character and bond order?

Which of the following statements is correct?

Which of the following molecular orbitals has two nodal planes?

According to the Molecular Orbital Theory,which of the following does not exist?

The electronic configuration of the $N_2$ molecule in its ground state can be written as: $KK[\sigma 2s^2 \sigma^* 2s^2 \pi 2p_x^2 \pi 2p_y^2 \sigma 2p_z^2]$. What is the bond order of the $N_2$ molecule?

Vedclass Test Series

Exam Paper Generator

Online Exam Module