The order of decreasing ease of abstraction o | vedclass

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(B) The ease of abstraction of a hydrogen atom depends on the stability of the resulting radical or carbocation intermediate. Abstraction of $H_{a}$ l

Vedclass · Accepted Answer

$H_{a} > H_{c} > H_{b}$

Vedclass · Answer

(B) The ease of abstraction of a hydrogen atom depends on the stability of the resulting radical or carbocation intermediate. Abstraction of $H_{a}$ leads to a $3^{\circ}$ allylic radical/carbocation, which is highly stable due to resonance and hyperconjugation. Abstraction of $H_{c}$ leads to a $2^{\circ}$ allylic radical/carbocation, which is less stable than the $3^{\circ}$ allylic species. Abstraction of $H_{b}$ leads to a $2^{\circ}$ non-allylic radical/carbocation, which is the least stable among the three. Therefore, the order of decreasing ease of abstraction is $H_{a} > H_{c} > H_{b}$.

The order of decreasing ease of abstraction of hydrogen atoms in the following molecule is:

Similar Questions

What is the increasing order of stability for the carbanions $P: \bar{C}H_3$,$Q: C_6H_5\bar{C}H_2$,$R: (CH_3)_2\bar{C}H$,and $S: H_2\bar{C}^{-}CH=CH_2$?

The species $A$,$B$,$C$,$D$ formed in the following bond cleavages respectively are:

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The increasing order of stability of the following free radicals is:

Which of the following orders regarding relative stability of free radicals is correct?

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