The point of intersection of the line frac{x | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the given line be $\frac{x - 1}{3} = \frac{y + 2}{4} = \frac{z - 3}{-2} = k$. Any point on the line is given by $(x, y, z) = (3k + 1, 4k - 2,

Vedclass · Accepted Answer

$(10, 10, -3)$

Vedclass · Answer

(B) Let the given line be $\frac{x - 1}{3} = \frac{y + 2}{4} = \frac{z - 3}{-2} = k$. Any point on the line is given by $(x, y, z) = (3k + 1, 4k - 2, -2k + 3)$. Since this point lies on the plane $2x - y + 3z - 1 = 0$,it must satisfy the plane equation: $2(3k + 1) - (4k - 2) + 3(-2k + 3) - 1 = 0$. Expanding the equation: $6k + 2 - 4k + 2 - 6k + 9 - 1 = 0$. Simplifying: $-4k + 12 = 0$,which gives $4k = 12$,so $k = 3$. Substituting $k = 3$ back into the point coordinates: $x = 3(3) + 1 = 10$,$y = 4(3) - 2 = 10$,$z = -2(3) + 3 = -3$. Thus,the point of intersection is $(10, 10, -3)$.

The point of intersection of the line $\frac{x - 1}{3} = \frac{y + 2}{4} = \frac{z - 3}{-2}$ and the plane $2x - y + 3z - 1 = 0$ is

Similar Questions

The $RNA$ can be removed by treatment with ............. whereas proteins can be removed by treatment with .............. in the isolation of $DNA$ from a cell.

$A$ particle is projected up along a rough inclined plane of inclination $45^{\circ}$ with the horizontal. If the coefficient of friction is $0.5$, the acceleration is ($g=$ Acceleration due to gravity).

If $x = 2^{1/3} - 2^{-1/3}$,then $2x^3 + 6x = $

When ethanol is reacted with $PCl_5$,it gives $A$,$POCl_3$,and $HCl$. The reaction of $A$ with silver nitrite $(AgNO_2)$ gives the major product $(B)$ and $AgCl$. What are $A$ and $B$ respectively?

The pairs of straight lines $x^2-3xy+2y^2=0$ and $x^2-3xy+2y^2+x-2=0$ form a

Vedclass Test Series

Exam Paper Generator

Online Exam Module