The value of 3 tan^{-1}(1/2) is equal to: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Step $1$: Use the formula $3 	an^{-1}(x) = 	an^{-1}\left(\frac{3x - x^3}{1 - 3x^2}ight)$.Step $2$: Substitute $x = 1/2$ into the formula.Step

Vedclass · Accepted Answer

$	an^{-1}(11/2)$

Vedclass · Answer

(D) Step $1$: Use the formula $3 	an^{-1}(x) = 	an^{-1}\left(\frac{3x - x^3}{1 - 3x^2}ight)$.Step $2$: Substitute $x = 1/2$ into the formula.Step $3$: Calculate the numerator: $3(1/2) - (1/2)^3 = 3/2 - 1/8 = 12/8 - 1/8 = 11/8$.Step $4$: Calculate the denominator: $1 - 3(1/2)^2 = 1 - 3/4 = 1/4$.Step $5$: The expression becomes $	an^{-1}\left(\frac{11/8}{1/4}ight) = 	an^{-1}\left(\frac{11}{8} 	imes 4ight) = 	an^{-1}(11/2)$.

The value of $3 \tan^{-1}(1/2)$ is equal to:

Similar Questions

If $4\sin^{-1}x + \cos^{-1}x = \pi$,then $x$ is equal to

If $\sin^{-1} x = \theta + \beta$ and $\sin^{-1} y = \theta - \beta$,then $1 + xy = $

The value of $\cot ^{-1}(-\sqrt{3})-\tan ^{-1} \sqrt{3}$ is equal to . . . . . . .

The value of $\tan \left(\frac{\pi}{4}+\frac{1}{2} \cos ^{-1}\left(\frac{a}{b}\right)\right)+\tan \left(\frac{\pi}{4}-\frac{1}{2} \cos ^{-1}\left(\frac{a}{b}\right)\right)$ is

$\sinh^{-1}\left(\frac{x}{\sqrt{1-x^2}}\right)$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module