Unpolarized light of intensity 32 W m^{-2} p | vedclass

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(B) The angle between the transmission axes of $P_1$ and $P_2$ is $	heta_1 = 30^\circ$ (given).The transmission axis of the last polarizer $P_3$ is c

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$3$

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(B) The angle between the transmission axes of $P_1$ and $P_2$ is $	heta_1 = 30^\circ$ (given).The transmission axis of the last polarizer $P_3$ is crossed with the first polarizer $P_1$,meaning the angle between $P_1$ and $P_3$ is $90^\circ$.Therefore,the angle between the transmission axes of $P_2$ and $P_3$ is $	heta_2 = 90^\circ - 30^\circ = 60^\circ$.The intensity of light transmitted by the first polarizer $P_1$ is $I_1 = \frac{I_0}{2} = \frac{32}{2} = 16 \ W m^{-2}$.According to Malus' law,the intensity of light transmitted by $P_2$ is $I_2 = I_1 \cos^2(30^\circ) = 16 	imes (\frac{\sqrt{3}}{2})^2 = 16 	imes \frac{3}{4} = 12 \ W m^{-2}$.Similarly,the intensity of light transmitted by $P_3$ is $I_3 = I_2 \cos^2(60^\circ) = 12 	imes (\frac{1}{2})^2 = 12 	imes \frac{1}{4} = 3 \ W m^{-2}$.

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