What is the value of 999 frac{1}{2} + 999 fra | vedclass

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Question

(D) The given expression is $999 \frac{1}{2} + 999 \frac{1}{6} + 999 \frac{1}{12} + 999 \frac{1}{20} + 999 \frac{1}{30}$.This can be written as $(999

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$4995 \frac{5}{6}$

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(D) The given expression is $999 \frac{1}{2} + 999 \frac{1}{6} + 999 \frac{1}{12} + 999 \frac{1}{20} + 999 \frac{1}{30}$.This can be written as $(999 + \frac{1}{2}) + (999 + \frac{1}{6}) + (999 + \frac{1}{12}) + (999 + \frac{1}{20}) + (999 + \frac{1}{30})$.Grouping the whole numbers and fractions: $(999 	imes 5) + (\frac{1}{2} + \frac{1}{6} + \frac{1}{12} + \frac{1}{20} + \frac{1}{30})$.$999 	imes 5 = 4995$.Now,sum the fractions: $\frac{1}{1 	imes 2} + \frac{1}{2 	imes 3} + \frac{1}{3 	imes 4} + \frac{1}{4 	imes 5} + \frac{1}{5 	imes 6}$.Using the formula $\frac{1}{n(n+1)} = \frac{1}{n} - \frac{1}{n+1}$,we get: $(1 - \frac{1}{2}) + (\frac{1}{2} - \frac{1}{3}) + (\frac{1}{3} - \frac{1}{4}) + (\frac{1}{4} - \frac{1}{5}) + (\frac{1}{5} - \frac{1}{6})$.This simplifies to $1 - \frac{1}{6} = \frac{5}{6}$.Therefore,the total value is $4995 + \frac{5}{6} = 4995 \frac{5}{6}$.

What is the value of $999 \frac{1}{2} + 999 \frac{1}{6} + 999 \frac{1}{12} + 999 \frac{1}{20} + 999 \frac{1}{30}$?

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