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(A) diode is forward-biased when the potential at the $p$-side (anode) is higher than the potential at the $n$-side (cathode).$(A)$ $p$-side = $-10 \

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$(B)$ and $(C)$ only

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(A) diode is forward-biased when the potential at the $p$-side (anode) is higher than the potential at the $n$-side (cathode).$(A)$ $p$-side = $-10 \ V$, $n$-side = $0 \ V$. Since $-10 $(B)$ $p$-side = $-10 \ V$, $n$-side = $-15 \ V$. Since $-10 > -15$, it is forward-biased.$(C)$ $p$-side = $4 \ V$, $n$-side = $2 \ V$. Since $4 > 2$, it is forward-biased.$(D)$ $p$-side = $-5 \ V$, $n$-side = $-10 \ V$. The diode symbol is reversed (pointing left), so the $n$-side is at $-5 \ V$ and the $p$-side is at $-10 \ V$. Since $-10 $(E)$ $p$-side = $0 \ V$ (ground), $n$-side = $2 \ V$. Since $0 Therefore, only circuits $(B)$ and $(C)$ are forward-biased.

Which of the following circuits represents a forward-biased diode? Choose the correct answer from the options given below.

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