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(B) semiconductor diode is reverse biased when the potential of the $P$-side is lower than the potential of the $N$-side $(V_P < V_N)$.Let's analyze e

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(B) semiconductor diode is reverse biased when the potential of the $P$-side is lower than the potential of the $N$-side $(V_P Let's analyze each option:$(A)$ $V_P = 0 \ V$,$V_N = -5 \ V$. Here $V_P > V_N$,so it is forward biased.$(B)$ $V_P = 0 \ V$,$V_N = 10 \ V$. Here $V_P $(C)$ $V_P = 10 \ V$,$V_N = 5 \ V$. Here $V_P > V_N$,so it is forward biased.$(D)$ $V_P = -5 \ V$,$V_N = -15 \ V$. Here $V_P > V_N$ (since $-5 > -15$),so it is forward biased.Therefore,the correct option is $(B)$.

Which of the following semiconductor diodes is reverse biased?

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