$2{\tan ^{ - 1}}\frac{1}{3} + {\tan ^{ - 1}}\frac{1}{2} = $

  • A
    $90^o$
  • B
    $60^o$
  • C
    $45^o$
  • D
    $\tan ^{ - 1}2$

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Similar Questions

$\frac{d}{dx} \left( \tan^{-1} \left( \frac{\cos x}{1 + \sin x} \right) \right) =$

સાબિત કરો કે $\sin ^{-1}(2 x \sqrt{1-x^{2}})=2 \cos ^{-1} x$,જ્યાં $\frac{1}{\sqrt{2}} \leq x \leq 1$.

જો $\tan ^{-1} x + \tan ^{-1} y + \tan ^{-1} z = \frac{\pi}{2}$,જ્યાં $x, y, z > 0$ અને $xy < 1$ હોય,તો $xy + yz + zx$ ની કિંમત શોધો:

સમીકરણ $\sin ^{-1}\left(\sum_{i=1}^{\infty} x^{i+1}-x \sum_{i=1}^{\infty}\left(\frac{x}{2}\right)^i\right)=\frac{\pi}{2}-\cos ^{-1}\left(\sum_{i=1}^{\infty}\left(-\frac{x}{2}\right)^i-\sum_{i=1}^{\infty}(-x)^i\right)$ ના અંતરાલ $\left(-\frac{1}{2}, \frac{1}{2}\right)$ માં રહેલા વાસ્તવિક ઉકેલોની સંખ્યા . . . . . છે.

જો $\sum_{n=1}^{2026} \tan^{-1}(\frac{1}{n^2+n+1}) = \tan^{-1}(1 - \frac{1}{x})$, જ્યાં $x \neq 0$, તો $x = $

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