$\int(\sqrt{x+\sqrt{12x-36}}+\sqrt{x-\sqrt{12x-36}}) dx=$

  • A
    $2\sqrt{3}x+C, \forall x$
  • B
    $\frac{4(x-3)^{3/2}}{3}+C, \forall x$
  • C
    $\begin{cases} \frac{4}{3}(x-3)^{3/2}+C, & \text{જો } x > 6 \\ 2\sqrt{3}x+C, & \text{જો } 3 \leq x \leq 6 \end{cases}$
  • D
    $\begin{cases} \frac{4}{3}(x-3)^{3/2}+C, & \text{જો } 3 \leq x \leq 6 \\ 2\sqrt{3}x+C, & \text{જો } x > 6 \end{cases}$

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Similar Questions

$\int \frac{dx}{\sin(x-a) \cos(x-b)} = $

$I = \int_{0}^{\frac{\pi}{4}} \tan^{n+1} x \, dx + \frac{1}{2} \int_{0}^{\frac{\pi}{2}} \tan^{n-1} \left( \frac{x}{2} \right) \, dx$ ની કિંમત શોધો.

જો $\int \frac{dx}{(x \tan x + 1)^2} = f(x) + c$ હોય,તો $\lim_{x \rightarrow \frac{\pi}{2}} f(x) = $

વિધેયનું સંકલન કરો: $\frac{x-1}{\sqrt{x^{2}-1}}$

કોઈપણ પૂર્ણાંક $n \geq 2$ માટે, ધારો કે $I_n = \int \tan^n x \, dx$. જો $n \geq 2$ માટે $I_n = \frac{1}{a} \tan^{n-1} x - b I_{n-2}$ હોય, તો ક્રમયુક્ત જોડ $(a, b)$ બરાબર છે

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