$\lim _{x \rightarrow-\infty} \frac{3|x|-x}{|x|-2 x} - \lim _{x \rightarrow 0} \frac{\log (1+x^3)}{\sin ^3 x} =$

  • A
    $1$
  • B
    $\frac{1}{3}$
  • C
    $\frac{4}{3}$
  • D
    $0$

Explore More

Similar Questions

यदि $\lim _{x \rightarrow \infty}\left(\left(\frac{e}{1-e}\right)\left(\frac{1}{e}-\frac{x}{1+x}\right)\right)^x=\alpha$ है,तो $\frac{\log _e \alpha}{1+\log _e \alpha}$ का मान ज्ञात कीजिए:

यदि $\mathop {Lim}\limits_{x \to {0^ - }} \sin^{-1}([\tan x])$ $= l$ है,तो $\{l\}$ का मान ज्ञात कीजिए,जहाँ $[\cdot]$ और $\{\cdot\}$ क्रमशः महत्तम पूर्णांक और भिन्नात्मक भाग फलन को दर्शाते हैं।

$\mathop {\lim }\limits_{x \to \infty } {\left( {1 + \frac{2}{x}} \right)^x} = $

$\lim _{x \rightarrow 1} (1 + \log _{e} x)^{1 / \log _{e} x}$ का मान ज्ञात कीजिए।

$\lim _{x \rightarrow 0} \frac{1-\cos x \cos 2 x}{\sin ^2 x} = $

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo