$A$ uniform cube is subjected to volume compression. If each side is decreased by $1\%$,then the bulk strain is

The bulk modulus of a liquid is $3 \times 10^{10} \ Nm^{-2}$. The pressure required to reduce the volume of liquid by $2 \%$ is ........ $\times 10^{8} \ Nm^{-2}$.

If the average depth of an ocean is $4000 \ m$ and the bulk modulus of water is $2 \times 10^9 \ N m^{-2}$,then the fractional compression $\frac{\Delta V}{V}$ of water at the bottom of the ocean is $\alpha \times 10^{-2}$. The value of $\alpha$ is . . . . . . (Given,$g=10 \ m s^{-2}, \rho=1000 \ kg m^{-3}$)

The average depth of the Indian Ocean is about $3000 \,m$. The value of fractional compression $\left(\frac{\Delta V}{V}\right)$ of water at the bottom of the ocean is (given that the bulk modulus of water is $2.2 \times 10^9 \,N/m^2$,$g = 9.8 \,m/s^2$,$\rho_{H_2O} = 1000 \,kg/m^3$):

$A$ spherical ball contracts in volume by $0.02 \%$, when subjected to a normal uniform pressure of $50 \text{ atm}$. The Bulk modulus of its material is ............. $Nm^{-2}$. (Take $1 \text{ atm} = 1.01 \times 10^5 \text{ Pa}$)

What is the pressure required to reduce the given volume of water by $1 \%$? (Bulk modulus $(K) = 2 \times 10^8 \ N m^{-2}$)