If the average depth of an ocean is $4000 \ m$ and the bulk modulus of water is $2 \times 10^9 \ N m^{-2}$,then the fractional compression $\frac{\Delta V}{V}$ of water at the bottom of the ocean is $\alpha \times 10^{-2}$. The value of $\alpha$ is . . . . . . (Given,$g=10 \ m s^{-2}, \rho=1000 \ kg m^{-3}$)
- A$1$
- B$2$
- C$4$
- D$7$
Explore More
Similar Questions
An object is located at $2 \, km$ beneath the surface of the water. If the fractional compression $\frac{\Delta V}{V}$ is $1.36 \, \%$,the ratio of hydraulic stress to the corresponding hydraulic strain will be ......... . [Given: density of water is $1000 \, kg \, m^{-3}$ and $g = 9.8 \, m \, s^{-2}$.]
The bulk modulus of rubber is $9.1 \times 10^8 \, N/m^2$. To what depth $h$ (in $m$) must a rubber ball be taken in a lake so that its volume is decreased by $0.1 \, \%$?
Medium
View Solution$A$ rubber ball is taken to a $100\, m$ deep lake and its volume changes by $0.1\%$. The bulk modulus of rubber is nearly
Medium
View SolutionIf the pressure on a body is increased from $200 \text{ kPa}$ to $250 \text{ kPa}$,the volume of the body decreases by $0.25 \%$. The compressibility of the material of the body is (in $m^2 \text{ N}^{-1}$)
When a rubber ball is taken to a depth of $h$ meters in deep sea,its volume decreases by $0.5\, \%$. Calculate the depth $h$. (Given: Bulk modulus of rubber $B = 9.8 \times 10^{8} \, \text{N/m}^2$,Density of sea water $\rho = 10^{3} \, \text{kg/m}^3$,$g = 9.8 \, \text{m/s}^2$)
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo