જો $y = \sin^{2} (\cot^{-1} \sqrt{\frac{1 + x}{1 - x}})$,હોય તો $\frac{dy}{dx} = $

  • A
    $\frac{- 1}{2}$
  • B
    $\frac{1}{1 + x}$
  • C
    $\frac{1}{1 - x}$
  • D
    $1$

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