यदि $y = \log_{10}x + \log_x 10 + \log_x x + \log_{10} 10$ है,तो $\frac{dy}{dx} = $

  • A
    $\frac{1}{x \ln 10} - \frac{\ln 10}{x (\ln x)^2}$
  • B
    $\frac{1}{x \ln 10} - \frac{1}{x \log_{10} e}$
  • C
    $\frac{1}{x \ln 10} + \frac{\ln 10}{x (\ln x)^2}$
  • D
    इनमें से कोई नहीं

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निम्नलिखित कथनों पर विचार करें:
कथन $1$: यदि $y = \log_{10} x + \log_{e} x$ है,तो $\frac{dy}{dx} = \frac{\log_{10} e}{x} + \frac{1}{x}$.
कथन $2$: $\frac{d}{dx}(\log_{10} x) = \frac{\log x}{\log 10}$ और $\frac{d}{dx}(\log_{e} x) = \frac{\log x}{\log e}$.

अवकलन ज्ञात कीजिए: $\frac{d}{dx}(\log_7(\log_7 x))$

$\log_{10} x$ का $\log_x 10$ के सापेक्ष अवकलज है

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