જો $y = \sec^{-1}\left( \frac{x + 1}{x - 1} \right) + \sin^{-1}\left( \frac{x - 1}{x + 1} \right)$ હોય,તો $\frac{dy}{dx} = $

  • A
    $0$
  • B
    $1$
  • C
    $2$
  • D
    $3$

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Similar Questions

$\cos ^{-1}\left(\frac{-1}{2}\right)-2 \sin ^{-1}\left(\frac{1}{2}\right)+3 \cos ^{-1}\left(\frac{-1}{\sqrt{2}}\right)-4 \tan ^{-1}(-1)$ ની કિંમત શોધો.

$\tan \left(2 \tan ^{-1}\left(\frac{3}{5}\right)+\sin ^{-1}\left(\frac{5}{13}\right)\right)$ ની કિંમત શોધો:

કિંમત શોધો: $\sin ^{-1}\left[\sin \left(-600^{\circ}\right)\right]+\cot ^{-1}(-\sqrt{3})$

જો $x, y, z$ એ $A.P.$ માં હોય અને $\tan ^{-1} x, \tan ^{-1} y, \tan ^{-1} z$ પણ $A.P.$ માં હોય,તો

જો $0 \leq x \leq \frac{1}{2}$ હોય,તો $\tan \left[\sin ^{-1}\left\{\frac{x}{\sqrt{2}}+\frac{\sqrt{1-x^{2}}}{\sqrt{2}}\right\}-\sin ^{-1} x\right]$ ની કિંમત શોધો.

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