यदि $y = \cos^{-1}(\sin x)$, जहाँ $\frac{\pi}{2} < x < \pi$, तो $\frac{dy}{dx} = \dots$
- A$-1$
- B$0$
- C$1$
- D$2$
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$x$ का वह मान जिसके लिए $\sin(\cot^{-1}(1 + x)) = \cos(\tan^{-1}x)$ है,वह है
$\cos ^{-1}\left(\cos \frac{13 \pi}{6}\right)+\tan ^{-1}\left(\tan \frac{7 \pi}{6}\right)=$ . . . . . . .
$\tan ^{-1}\left(\tan \frac{31 \pi}{6}\right)=$ . . . . . . .
यदि $4 \sin ^{-1} x + 6 \cos ^{-1} x = 3 \pi$,जहाँ $-1 \leq x \leq 1$,तो $x =$
$\cos ^{-1}\left(-\frac{1}{\sqrt{2}}\right)$ का मुख्य मान ज्ञात कीजिए।
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