The octahedral complex of a metal ion M^{3+} | vedclass

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Question

(B) The crystal field splitting energy $(\Delta_o)$ is inversely proportional to the wavelength $(\lambda)$ of the light absorbed: $\Delta_o = \frac{h

Vedclass · Accepted Answer

$L_1 < L_3 < L_2 < L_4$

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(B) The crystal field splitting energy $(\Delta_o)$ is inversely proportional to the wavelength $(\lambda)$ of the light absorbed: $\Delta_o = \frac{hc}{\lambda}$.Stronger ligands cause greater splitting and thus absorb light of shorter wavelengths.The order of wavelengths for the given colors is: $ ext{Red} (L_1) > ext{Yellow} (L_3) > ext{Green} (L_2) > ext{Blue} (L_4)$.Since ligand strength $\propto \frac{1}{\lambda}$,the increasing order of ligand strength is: $L_1 < L_3 < L_2 < L_4$.

$I$	$II$
$(a). [Cr(H_2O)_6]^{2+}$	$[Cr(H_2O)_6]^{3+}$
$(b). [Fe(H_2O)_6]^{3+}$	$[Fe(CN)_6]^{3-}$
$(c). [Fe(CN)_6]^{3-}$	$[Ru(CN)_6]^{3-}$
$(d). [NiF_6]^{4-}$	$[NiF_6]^{2-}$

The octahedral complex of a metal ion $M^{3+}$ with four monodentate ligands $L_1, L_2, L_3$ and $L_4$ absorb wavelengths in the region of red,green,yellow and blue,respectively. The increasing order of ligand strength of the four ligands is:

Similar Questions

The order of absorption wavelength in the visible region for the following complexes is:

The crystal field splitting energy of $[Co(oxalate)_3]^{3-}$ complex is '$n$' times that of the $[Cr(oxalate)_3]^{3-}$ complex. Here '$n$' is [Assume $\Delta_0 \gg P$].

For which of the following complexes will the value of $\Delta_0$ be the lowest?

Which among the following complexes is associated with the maximum wavelength of light absorbed?

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