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(D) $1$. Stress is defined as force per unit area $(Stress = F/A)$. Since both wires have the same diameter $d$,they have the same cross-sectional are

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same stress but different strain

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(D) $1$. Stress is defined as force per unit area $(Stress = F/A)$. Since both wires have the same diameter $d$,they have the same cross-sectional area $A = \pi(d/2)^2$. When a force $F$ is applied to the combined wire,the same force $F$ acts on each wire. Therefore,both wires experience the same stress.$2$. Strain is defined as the ratio of change in length to the original length $(Strain = \Delta L / L)$. The relationship between stress and strain is given by Hooke's Law: $Stress = Y 	imes Strain$,where $Y$ is the Young's modulus of the material.$3$. Since the wires are made of different materials,they have different Young's moduli $(Y_1 
eq Y_2)$.$4$. Because $Strain = Stress / Y$,and the stress is the same for both but the Young's moduli are different,the strain in the two wires must be different.$5$. Thus,the wires have the same stress but different strain.

Two wires of different materials have same length $L$ and same diameter $d$. The second wire is connected at the end of the first wire and forms one single wire of double the length. This wire is subjected to a stretching force $F$ to produce an elongation $\ell$. The two wires have:

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