જો alpha + beta + gamma = 2pi હોય,તો | vedclass

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Question

(A) આપેલ છે કે $\alpha + \beta + \gamma = 2\pi$.$2$ વડે ભાગતા,આપણને $\frac{\alpha}{2} + \frac{\beta}{2} + \frac{\gamma}{2} = \pi$ મળે છે.બંને બાજુ ટેન

Vedclass · Accepted Answer

$	an \frac{\alpha }{2} + 	an \frac{\beta }{2} + 	an \frac{\gamma }{2} = 	an \frac{\alpha }{2}	an \frac{\beta }{2}	an \frac{\gamma }{2}$

Vedclass · Answer

(A) આપેલ છે કે $\alpha + \beta + \gamma = 2\pi$.$2$ વડે ભાગતા,આપણને $\frac{\alpha}{2} + \frac{\beta}{2} + \frac{\gamma}{2} = \pi$ મળે છે.બંને બાજુ ટેન્જન્ટ લેતા,આપણને $	an \left( \frac{\alpha}{2} + \frac{\beta}{2} + \frac{\gamma}{2} ight) = 	an \pi = 0$ મળે છે.સૂત્ર $	an(A+B+C) = \frac{\sum 	an A - \prod 	an A}{1 - \sum 	an A 	an B}$ નો ઉપયોગ કરતા:$\frac{	an \frac{\alpha}{2} + 	an \frac{\beta}{2} + 	an \frac{\gamma}{2} - 	an \frac{\alpha}{2} 	an \frac{\beta}{2} 	an \frac{\gamma}{2}}{1 - (	an \frac{\alpha}{2} 	an \frac{\beta}{2} + 	an \frac{\beta}{2} 	an \frac{\gamma}{2} + 	an \frac{\gamma}{2} 	an \frac{\alpha}{2})} = 0$.અંશ $0$ હોવો જોઈએ,તેથી:$	an \frac{\alpha}{2} + 	an \frac{\beta}{2} + 	an \frac{\gamma}{2} - 	an \frac{\alpha}{2} 	an \frac{\beta}{2} 	an \frac{\gamma}{2} = 0$.તેથી,$	an \frac{\alpha}{2} + 	an \frac{\beta}{2} + 	an \frac{\gamma}{2} = 	an \frac{\alpha}{2} 	an \frac{\beta}{2} 	an \frac{\gamma}{2}$.

જો $\alpha + \beta + \gamma = 2\pi$ હોય,તો

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