$1 + \frac{4^2}{3!} + \frac{4^4}{5!} + \dots \infty = $

  • A
    $\frac{e^4 + e^{-4}}{4}$
  • B
    $\frac{e^4 - e^{-4}}{4}$
  • C
    $\frac{e^4 + e^{-4}}{8}$
  • D
    $\frac{e^4 - e^{-4}}{8}$

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Similar Questions

${\left[ {1 + \frac{1}{{2!}} + \frac{1}{{4!}} + \dots \infty } \right]^2} - {\left[ {1 + \frac{1}{{3!}} + \frac{1}{{5!}} + \dots \infty } \right]^2} = $

$1+\frac{1+2}{2 !}+\frac{1+2+2^2}{3 !}+\ldots$ ની કિંમત શોધો.

$\frac{1}{1!} + \frac{1 + 2}{2!} + \frac{1 + 2 + 2^2}{3!} + .....\infty = $

શ્રેણી $\frac{1}{2!} - \frac{1}{3!} + \frac{1}{4!} - \dots$ નો અનંત પદ સુધીનો સરવાળો શોધો.

Difficult
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ધારો કે $C(\theta) = \sum_{n=0}^{\infty} \frac{\cos(n\theta)}{n!}$. નીચેનામાંથી કયું વિધાન ખોટું છે?

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